Armstrong Number in Java

A positive number is called an Armstrong number if it is equal to the sum of the cubes of its digits, for example, 0, 1, 153, 370, 371, 407, etc.

In other words, the following equation will be verified

xy..z = xⁿ + yⁿ + ….. + zⁿ

n is the number of digits

For example, 370 is a 3-digit Armstrong number

370 = 3³ + 7³ + 0³
        = 27 + 343 + 0
        = 370

Now we will see Armstrong’s implementation in Java.
 

 

Program to check if the given number is an Armstrong number

public class NbrArmstrong {

    public static void main(String[] args) {

        int n = 370;
        int nbr = n;
        int tmp; 
        int sum = 0;
      
        while (nbr != 0)
        {
            tmp = nbr % 10;
            sum = sum + tmp*tmp*tmp;
            nbr /= 10;
        }

        if(sum == n)
            System.out.println(n + " is an Armstrong number");
        else
            System.out.println(n + " is not an Armstrong number");
    }
}

Output:

370 is an Armstrong number

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