Python Program to Check if a Year is a Leap Year

In this tutorial, we are going to see how to write a Python program to check if the input year (entered by the user) is a leap year or not.

You can check if a year is a leap year or not using this mathematical logic:
 
Leap Year:

• If a year is divisible by 4, 100 and 400, it is a leap year.
• If a year is divisible by 4 but not by 100, it is a leap year.

Not a leap year:

• If a year is not divisible by 4, it is not a leap year.
• If a year is divisible by 4 and 100 but not by 400, it is not a leap year.

 

Python Program to Check if a Year is a Leap Year

In this program, the user is prompted to enter a year. The program checks if the entered year is a leap year or not.

year = int(input("Enter the year to verify:"))

if(year%4==0 and year%100!=0 or year%400==0):
    print("The year is a leap year!")
else:
    print("The year is not a leap year!")

Output:

Enter the year to verify: 2016
The year is a leap year!

Enter the year to verify: 2005
The year is not a leap year!

1. The user must first enter the year to be checked.
2. The if statement checks if the year is a multiple of 4 but not a multiple of 100 or if it is a multiple of 400 (because not every year, a multiple of 4 is a leap year).
3. The result is then displayed.

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