Leap Year Program in C

In this tutorial, we are going to see how to write a C program to check if the input year (entered by the user) is a leap year or not.

You can check if a year is a leap year or not using this mathematical logic:
 
Leap Year:

• If a year is divisible by 4, 100 and 400, it is a leap year.
• If a year is divisible by 4 but not by 100, it is a leap year.

Not a leap year:

• If a year is not divisible by 4, it is not a leap year.
• If a year is divisible by 4 and 100 but not by 400, it is not a leap year.

 

C Program to Check if a Year is a Leap Year

In this program, the user is prompted to enter a year. Then the program checks if the entered year is a leap year or not.

#include <stdio.h>

int main()
{
    int year;

    printf("Enter a year: ");
    scanf("%d",&year);

    if(year % 4 == 0)
    {
        if( year % 100 == 0)
        {
            if ( year % 400 == 0)
                printf("%d is a leap year", year);
            else
                printf("%d not a leap year", year);
        }
        else
            printf("%d is a leap year", year );
    }
    else
        printf("%d not a leap year", year);

    return 0;
}

Output:

Enter a year: 2004
2004 is a leap year

1. The user must first enter the year to be checked.
2. The if statement checks if the year is a multiple of 4 but not a multiple of 100 or if it is a multiple of 400 (because not every year, a multiple of 4 is a leap year).
3. The result is then displayed.

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